Evaluate: $\mathop {\lim }\limits_{x \to 0} \frac{\sin 4x}{\sin 2x}$

  • A
    $1$
  • B
    $2$
  • C
    $4$
  • D
    $8$

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$\mathop {\lim }\limits_{x \to \frac{\pi }{2}} \frac{{\cot x - \cos x}}{{{{\left( {\pi - 2x} \right)}^3}}} = $ . . . .

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